Multiple Choice Question
Given the following script (for IPython Notebooks):
!cat count-stdin.py import sys count=0 for line in sys.stdin: count +=1 print count, 'lines in standard input'
Which of these choices will successfully give you the line count of the small.csv file?
a) ipython count-stdin.py small.csv b) !cat count-stdin.py small.csv c) %run count-stdin.py < small.csv d) !ipython count-stdin.py < small.csv e) %run count-stdin.py small.csv f) !ipython count-stdin.py | small.csv
Question #2
Given that you have three files (small-01.csv, small-02.csv, small-03.csv) that have this structure:
0,1,1 2,1,0
Debug the following script designed to create a function (readings.py) that could apply ---min, ---max and ---mean actions to multiple "small" files:
cat readings.py import sys import numpy def main(): script=sys.argv[0] action=sys.argv[1] filenames=sys.argv[2] assert action in ['--min", '--mean','--max'], Action is not one of --min, --mean, or --max: ' + action if len(filenames)==1 process(sys.stdin,action) else: for f in filenames: process(f,action) def process(filename, action): data=np.loadtxt(filename, delimiter=',') if action == 'min': values=data.min(axis=1) elif action == 'mean': values=data.mean(axis=1) elif action == 'max': values=data.max(axis=1) for m in values: print m main()